# Question #d27c7

Jan 18, 2018

OK, we can work this out.

#### Explanation:

If $y = 20 \mathmr{and} x = 8$ then as $20 = 2.5 \times 8$ so $y = 2.5 \times x$

Let’s use that to find y if x = 76, knowing that y is always two and a half times bigger than x.

$y = 2.5 \times 76 = 190$

Jan 20, 2018

$y = 190$

#### Explanation:

Set up a proportion.

$\frac{8}{20} = \frac{76}{y}$

Cross multiply.
Multiply each numerator by the opposite denominator.

$\left(8 \times y\right) = \left(76 \times 20\right)$

Simplify.

$8 y = 1520$

Divide both sides by $8$.

$\frac{8 y}{8} = \frac{1520}{8}$

Cancel $8$ on the left-hand side.

$\frac{{\textcolor{red}{\cancel{\textcolor{b l a c k}{8}}}}^{1} y}{\textcolor{red}{\cancel{\textcolor{b l a c k}{8}}}} ^ 1 = \frac{1520}{8}$

Simplify.

$y = 190$