# Question #6c539

$5 A$
Current ($I$) is given as $\frac{q}{t}$ ,where $q$ is the charge flowing through the resistor and $t$ is time in second.
given, $q$ = $1200 C$ and $t = 4 m t s$ i.e $4 \cdot 60 s$
so, $I = \left(\frac{1200}{240}\right) A$ i.e $5 A$