Question

Question #a8475

Answer 1

`(cos^2x+sin^4x)/(sin^2x+cos^4x)`

`=>(1-sin^2+sin^4x)/(sin^2x+(1-sin^2x)^2)`

`=>(1-sin^2+sin^4x)/(sin^2x+1-2sin^2x+sin^4x)`

`=>(1-sin^2+sin^4x)/(1-sin^2x+sin^4x)=1`