Question #3a7d0

1 Answer
Jan 20, 2018

#(8sin theta+5 cos theta)/(sin^3 theta-2cos^3 theta+7 cos theta)#

#=((8sin theta)/cos^3theta+(5 cos theta)/cos^3theta)/((sin^3 theta)/cos^3theta-(2cos^3 theta)/cos^3theta+(7 cos theta)/cos^3theta)#

#=(8tanthetasec^2theta+5 sec^2theta)/(tan ^3theta-2+7sec^2theta)#

#=(8tantheta(1+tan^2theta)+5 (1+tan^2theta))/(tan ^3theta-2+7(1+tan^2theta)#

#=(8*1(1+1^2)+5 (1+1^2))/(1 ^3theta-2+7(1+1^2)#

#=(16+5*2)/(1 -2+7*2)#

#=26/13=2#