Question #ff1a3

1 Answer
Jan 21, 2018

#csc52/sec38 + 2/sqrt3*tan38*tan60*tan52-3( sin^2 32 + sin^2 58) #

#=csc52/sec(90-52) + 2/sqrt3*tan38*sqrt3*tan(90-38)-3( sin^2 32 + sin^2(90- 32) #
#=csc52/csc52 + 2/sqrt3*tan38*sqrt3*cot38-3( sin^2 32 + cos^2 32) #

#=1 + 2-3*1=0 #