Question #0421a

1 Answer
Jim G.
Jan 22, 2018

#"length "=6" and width "=2#

Explanation:

#•color(white)(x)"perimeter "=(2xx"length")+(2xx"width")#

#"let width "=w#

#"then length "=3wlarrcolor(blue)"three times the width"#

#rArr"perimeter "=(2xx3w)+(2xxw)#

#color(white)(xxxxxxxxxx)=6w+2w=8w#

#"now perimeter "=16#

#rArr8w=16#

#"divide both sides by 8"#

#(cancel(8) w)/cancel(8)=16/8#

#rArrw=2#

#"and "3w=3xx2=6#

#rArr"width "=2" and length "=6#

#color(blue)"As a check"#

#"perimeter "=(2xx6)+(2xx2)=12+4=16" True"#

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