Question #57b7b

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Answer 1 · 2018-01-22T13:48:40

The angles are #alpha=2.238rad#, #beta=1.256# and #gamma=0.764#

The vector is

#vecu=-6hati+3hatj+7hatk#

The modulus is

#||vecu||=sqrt((-6-0)^2+(3-0)^2+(7-0)^2)=sqrt(36+9+49)=sqrt(94)#

#cosalpha=-6/sqrt(94)#

#=>#, #alpha=arccos(-6/sqrt94)=2.238rad#

#cosbeta=3/sqrt(94)#

#=>#, #beta=arccos(3/sqrt94)=1.256rad#

#cosgamma=7/sqrt(94)#

#=>#, #gamma=arccos(7/sqrt94)=0.764rad#