Question #7beaa

1 Answer
Jan 22, 2018

See the explanation below

Explanation:

The vector is

#vecv=((4),(1),(2))-((2),(8),(0))=((2),(-7),(2))#

#=2hati-7hatj+2hatk#

#=< 2, -7, 2>#

The magnitude of #vecu# is

#||vecv||=sqrt((2)^2+(-7)^2+(2)^2)=sqrt(4+49+4)=sqrt57#

The unit vector in the direction of #vecv# is

#hatv=vecv/(||vecv||)=1/sqrt57 <2,-7,2>#