How MIGHT #"1,6-dibromohexane"# react with alkali metal?

1 Answer
Jan 22, 2018

Well, we MIGHT get #"Wurtz coupling"# to get cyclohexane...

Explanation:

And thus....TWO equivs of alkali metal react with the dibromide to give...

#BrCH_2(CH_2)_4CH_2Br + 2Na stackrel(Delta, Et_2O)rarrBrCH_2(CH_2)_4CH_2^(-)Na^+ + NaBrdarr#

#BrCH_2(CH_2)_4CH_2^(-)Na^+ stackrel(-NaBr)rarr"cyclohexane"#

Will it work? Got me....you could always buy a bottle of cyclohexane for next to nothing.....