Question #9a866

1 Answer
Feb 24, 2018

#rarrsin120°=sin(180°-60°)=sin60°=sqrt(3)/2#

#rarrcos120°=cos(180°-60°)=-cos60°=-1/2#

#rarrsin240°=sin(180°+60°)=-sin60°=-sqrt(3)/2#

#rarrcos240°=cos(180°+60°)=-cos60°=-1/2#

#rarrsin300°=sin(360°-60°)=-sin60°=-sqrt(3)/2#

#rarrcos300°=cos(360°-60°)=cos60°=1/2#

Note #rarr#sin is not changed into cos and vice versa because we used #180°(90°*2)# and #360°(90°*4)# which are even multiples of #90°# and the sign of the angle is determined by the quadrant to which the angle lies.