Question #27836

1 Answer
Jan 23, 2018

Given

#f(x)= cosx+ sinx + 2#

#=>f(x)= sqrt2(1/sqrt2cosx+ 1/sqrt2sinx) + 2#

#=>f(x)= sqrt2(cos(pi/4)cosx+ sin(pi/4)sinx) + 2#

#=>f(x)= sqrt2cos(x-pi/4) + 2#

So #f(x)# is transformed into the following form
# f(x)= p cos (x-Φ) + q #,

Where #sqrt2=p ,pi/4=phiand 2=q#