Question

Question #381f0

Answer 1

See below.

Explanation:

Let `sin^-1(x)=A`

Then `sinA=x`

`rarrcscA=1/sinA=1/x`

`rarrA=csc^(-1)(1/x)`

`rarrsin^(-1)x=csc^(-1)(1/x)`

No, we cannot write `sin^-1(x)=cscx` because `sin^-1(x)` is an angle whereas `cscx` is a ratio of hypotenuse to perpendicular.