A #0.252g# mass of #"oxalic acid"# is titrated with a #41.35mL# volume of #"sodium hydroxide"#. What is the concentration of the sodium hydroxide solution?

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Answer 1 · 2018-01-23T07:15:16

#[NaOH]=0.135*mol*L^-1#

We need a stoichiometric equation to inform our ideas of equivalence, and it is a fact that oxalic acid is a DIACID...

#HO(O=)C-C(=O)OH(aq) +2NaOH(aq) rarr Na^(+)""^(-)O(O=)C-C(=O)O^(-)""^+Na +2H_2O#

#"[NaOH]"=(2xx(0.252*g)/(90.03*g*mol^-1))/(41.35xx10^-3*L)=0.135*mol*L^-1#

A #0.252*g# mass of #"oxalic acid"# is titrated with a #41.35*mL# volume of #"sodium hydroxide"#. What is the concentration of the sodium hydroxide solution?