Simplify #ln4+2ln4#?

2 Answers
Jan 24, 2018

#ln4+2ln4=ln64#

Explanation:

Remember two logarithmic identities,

  1. #log_ax+log_ay=log_axy# and
  2. #mlog_ax=log_ax^m#

Further #ln# is just #log# with base #e# and is better known as Napier's or natural log

Hence, #ln4+2ln4#

= #ln4+ln4^2#

= #ln(4xx4^2)#

= #ln64#

Jan 24, 2018

#ln64#

Explanation:

#"using the "color(blue)"laws of logarithms"#

#•color(white)(x)logx+logy=log(xy)#

#•color(white)(x)logx^nhArrnlogx#

#rArrln4+2ln4#

#=ln4+ln4^2#

#=ln(4xx4^2)#

#=ln64#