Question #a3f6b

1 Answer
P dilip_k
Jan 25, 2018

#sin2x-sinx-2cosx+1=0#

#=2sinxcosx-sinx-2cosx+1=0#

#=>sinx(2cosx-1)-1(2cosx-1)=0#

#=>(2cosx-1)(sinx-1)=0#

When #2cosx-1=0#

#=>cosx=1/2=cos(pi/3)#

#=>x=2npipmpi/3" where " nin ZZ#

When #sinx=1#

#=>x=kpi+(-1)^npi/2" where " kin Z#

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