Question #383fd

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Answer 1 · 2018-01-25T04:25:53

#3#

#1/2log_3(144)-log_3(4)+2log_3(3)#

Know that, #log_a(a)=1#

So, the equation becomes

#=1/2log_3(144)-log_3(4)+2*1#

#=1/2log_3(144)-log_3(4)+2#

Also know that, #mlog_a(c)=log_a(c^m)#

#:.1/2log_3(144)=log_3(144^(1/2))=log_3(12)#

#=log_3(12)-log_3(4)+2#

Another rule is that #log_a(c)-log_a(b)=log_a(c/b)#

#=log_3(12/4)+2#

#=log_3(3)+2#

#=1+2#

#=3#