Question #35edd

2 Answers
Jan 26, 2018

#x=4#

Explanation:

I'm assuming your problem is #5x=20#, because it looks like your trying to multiply #5# by a number but your number is missing, so I'm predicting that your question is #5x=20#.

In that case:

#5x=20#

Divide by #5# from both sides to eliminate #5# on the #LHS#.

#(cancel5x)/cancel5=20/5#

#20-:5=4#

#:.x=4#

Jan 26, 2018

The answer is #x=4#.

Explanation:

To solve one-variable equations like this one, you need to perform actions on both sides of the equation so that in the end, #x# is on one side of the#=#sign, and numbers are on the other.

In this case, we want to divide both sides of the equation by 5 in order to get #x# by itself, because to get from #5x# to #x#, you need to divide by 5.

#5x=20#

#5xcolor(red)(-:5)=20color(Red)(-:5)#

#cancel(5)x-:cancel(5) = 20-:5#

#x = 20-:5#

#x = 4#