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Answer 1 · 2018-01-26T06:46:35

#(sqrt85, tan^-1 (9/3))#

Given the complex number,

#2+9i#

we know that the modulus is #r=sqrt(x^2+y^2)# and the argument is #theta#=#tan^-1(y/x)#

Here

#y = 9# and #x = 2#

so

#r=sqrt(2^2+9^2) = sqrt(85)#

#theta=tan^-1 (9/2)#

The polar form of the complex number is #(sqrt85, tan^-1 (9/3))#