Question #f18f0

1 Answer
Jan 26, 2018

#sec^2beta#

Explanation:

#"using the "color(blue)"trigonometric identities"#

#•color(white)(x)secbeta=1/cosbeta#

#•color(white)(x)sin^2beta+cos^2beta=1#

#"divide all terms by "cos^2beta#

#(sin^2beta)/(cos^2beta)+(cos^2beta)/(cos^2beta)=1/(cos^2beta)#

#rArrtan^2beta+1=sec^2beta#