Question #a8bac

1 Answer
Jan 28, 2018

See below.

Explanation:

You can not solve this for a unique value of A.

Example:

#2=Ae^(kt)#

Here you have #3# variables, but only #1# equation.

For a unique solution. If there are:

#n# variables, you need #n# equations.

If you have #n-1# equations you will have to solve in terms of #1# variable.

If you have #n-2# equations you will have to solve in terms of #2# variables, and so on.

In this example we have #n=3# variables, and #n-2# equations.

So will solve in terms of #2# variables.

#2=Ae^(kt)#

Divide by #e^(kt)#

#2/(e^(kt))=A#

#A=2/(e^(kt))#

Assigning arbitrary values to #k# and #t# gives an infinite number of solutions.