Question #3a950
1 Answer
Jan 27, 2018
Given function
#u=(4x^2y^3)/z^4#
Tanking log of both sides.
#logu=log((4x^2y^3)/z^4)#
#logu=log4+logx^2+logy^3-logz^4#
Using theory of errors,remembering that errors are additive and differentiating each term with respect variable, we get
#(Deltau)/u=+-2(Deltax)/x+-3(Deltay)/y+-4(Deltaz)/z#
where#Deltau# is the error in#u# ans so on.
Assuming that given errors are respective percentage errors, percentage error in function
#+-9%#