Question #3a950

1 Answer
Jan 27, 2018

Given function

#u=(4x^2y^3)/z^4#

Tanking log of both sides.

#logu=log((4x^2y^3)/z^4)#
#logu=log4+logx^2+logy^3-logz^4#

Using theory of errors,remembering that errors are additive and differentiating each term with respect variable, we get

#(Deltau)/u=+-2(Deltax)/x+-3(Deltay)/y+-4(Deltaz)/z#
where #Deltau# is the error in #u# ans so on.

Assuming that given errors are respective percentage errors, percentage error in function #u# is

#+-9%#