How many irrational terms have #(sqrt2+sqrt3)^15 =# ?

1 Answer
Jan 27, 2018

#2#

Explanation:

#(sqrt2+sqrt3)^2=5+2sqrt6#

so all the even powers have one irrational term of type #n sqrt6#

For an odd power we have

#(a+b sqrt6)(sqrt2+sqrt3) = (a+3b)sqrt2+(a+2b)sqrt3#

with two irrational terms of type #n sqrt2, m sqrt3# then

#(sqrt2+sqrt3)^15 = m sqrt2+n sqrt3# with two irrational terms.