Question #583b0

1 Answer
Jan 28, 2018

Answer:

1.429 g/L

Explanation:

We know that one mole of any substance at STP will occupy a volume of #22.4# liters. We know that oxygen is diatomic, therefore one mole of oxygen weights #"32 g"#.

Apply the density formula:

#rho =m/V#

#rho =("32 g O"_2) /("22.4 L")#

You get

#rho = "1.42857 g/L"#

you round it up to #"1.429 g/L"#.