# Question #583b0

Jan 28, 2018

1.429 g/L

#### Explanation:

We know that one mole of any substance at STP will occupy a volume of $22.4$ liters. We know that oxygen is diatomic, therefore one mole of oxygen weights $\text{32 g}$.

Apply the density formula:

$\rho = \frac{m}{V}$

$\rho = \left(\text{32 g O"_2) /("22.4 L}\right)$

You get

$\rho = \text{1.42857 g/L}$

you round it up to $\text{1.429 g/L}$.