Question #a3e4b

1 Answer
Narad T.
Jan 28, 2018

See the proof below

Explanation:

We need

#cos^2A+sin^2A=1#

Therefore,

#LHS=(1+cosA)^2/(sinA)^2#

#=(1+cosA)^2/(sin^2A)#

#=(1+cosA)^2/(1-cos^2A)#

#=((1+cosA)cancel(1+cosA))/((1-cosA)cancel(1+cosA))#

#=(1+cosA)/(1-cosA)#

#=RHS#

#QED#

Related questions
Impact of this question
184 views around the world
You can reuse this answer
Creative Commons License