It is no true that if a function is continuous at a point #x=a# then it will also be differentiable at that point.
Take the example of the function #f(x)=absx# which is continuous at every point in its domain, particularly #x=0#.
We can derive that #f'(x)=absx/x#.
Obviously, #f'(x)# does not exist, but #f# is continuous at #x=0#, so the statement is false.
The converse is true, however. Any differentiable function is necessarily continuous.
Proof:
Let #f# be a differentiable function with derivative #f'# defined at every #x in "D"_f#. Then
#f'(x)=lim_(h→0) (f(x+h)-f(x))/h# is well defined
Now, #f# is continuous iff #lim_(x→c) f(x)=f(c)#. Consider #lim_(x→c)f(x)#
#lim_(x→c) f(x)=lim_(h→0)f(c+h)=lim_(h→0) h(f(c+h)-f(c))/h +f(c)=lim_(h→0)hf'(c)+f(c)=f(c)#
So #f# is continuous, as required. #square#