Question #3e331

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Answer 1 · 2018-01-29T14:35:08

#theta=23.58^@" or "theta=156.42^@#

#"given "sintheta=0.40#

#"since "sintheta>0#

#"then "theta" is in first/second quadrants"#

#rArrtheta=sin^-1(0.40)=23.58^@" to 2 dec. places"#

#"or "theta=(180-23.58)^2=156.42^@#

Answer 2 · 2018-01-29T19:23:05

#t = 23^@58, and t = 156^@42#

sin t = 0.40
Calculator gives --> #t = 23^@58#
Trig unit circle gives another t that has the same sin value (0.4)
#t = 180 - 23.58 = 156^@42#