Question #f9eec
1 Answer
Feb 4, 2018
# n^2x^2 + m^2y^2 -= 2m^2 n^2 sin^2 theta #
Explanation:
We have:
# x = m sin theta #
# y = n sin theta #
And so:
# n^2x^2 + m^2y^2 -= n^2(m sin theta)^2 + m^2(n sin theta)^2 #
# " " -= m^2 n^2 sin^2 theta + m^2 n^2 sin^2 theta #
# " " -= 2m^2 n^2 sin^2 theta #
