Question #b383f

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Answer 1 · 2018-01-29T19:13:53

#x = (3pi)/2+ 2npi; n in ZZ#

Given: #4 sin(x) - 1 = -5#

Add 1 to both sides:

#4sin(x) = -4#

Divide both sides by 4:

#sin(x) = -1#

Use the inverse sine function on both sides:

#x = sin^-1(-1)#

The primary value is:

#x = (3pi)/2#

Add the periodic behavior at integer multiples of #2pi#:

#x = (3pi)/2+ 2npi; n in ZZ#

Answer 2 · 2018-01-29T19:16:52

#x = (3pi)/2 + 2kpi#

4sin x = -5 + 1 = - 4
sin x = -1
Trig unit circle -->
#x = (3pi)/2 + 2kpi#
or #x = 270^@ + k360^@#