In a gaseous mixture the individual partial pressures are: #P_(N_2)=100*kPa; P_(CO_2)=24*kPa; P_(O_2)=30*kPa; P_(He)=26*kPa#. What is the total pressure, #P_"total"#, exerted by the mixture?

1 Answer
anor277
Jan 30, 2018

Well the one is easy....#P_"Total"=180*kPa...#

Explanation:

In a gaseous mixture, the total pressure is the sum of the individual partial pressures, the which we have been given...i.e. #P_"Total"=P_1+P_2+P_3...+P_n#

And thus #P_"Total"=P_(N_2)+P_(CO_2)+P_(O_2)+P_(He)#...and thus...

#P_"Total"={100+24+30+26}*kPa =??kPa#.......

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