Question

Question #35ee5

Answer 1

`tanx`

Explanation:

We have, putting on a common denominator:

`=(sin^3x + sinxcos^2x)/cosx`

Now:

`=(sinx(sin^2x + cos^2x))/cosx`

We know that `sin^2x+ cos^2x = 1`

`=sinx/cosx`

`=tanx`

Hopefully this helps!