Solve # 2ln 4 - 2ln(1/2)#?
1 Answer
Feb 1, 2018
Firstly a terminology primer, we solve equations but we simplify expressions.
Using the logarithm property:
#log a^b = bloga #
We can simplify the given expression as follows
# 2ln 4 - 2ln(1/2) = 2ln 2^2 - 2ln(2^(-1)) #
# \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 2(2)ln 2 - 2(-1)ln2 #
# \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 4ln 2 +2ln2 #
# \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 6ln2 #
