Question #905d0

2 Answers
Feb 3, 2018

No.

Explanation:

Remember this rule:

If you have a triangle with sides #ABC#, then

#A+B>C#

#A+C>B#

#B+C>A#

#abs (A-B) < C #

#abs(A-C)< B #

#abs (B-C) < A #

Let's name #A# our 2in side, #B# 3in side, #C# 6 in side.

Let's try our rule out.

#2+3<6#

#2+6>3#

#3+6>2#

#abs (2-3) < 6 #

#abs(2-6) > 3 #

#abs (3-6) > 2 #

We see that three inequalities do not go with our rule. Therefore, it is impossible to construct this triangle.

Feb 3, 2018

No; the sum of the lengths of the two shortest sides must be greater that the length to the longest side to form a triangle.

Explanation:

For the given dimensions, if two vertices of the triangle are a distance of 6 inches apart,
the third point must be 2 inches from one end and 3 inches from the other end:
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As can be seen there is no point which is both 2 inches from one end and 3 inches from the other.