Question #2835f

2 Answers
Ujjwal
Feb 3, 2018

See below

Explanation:

#2sinA = sqrt3#

# sinA = sqrt3/2#

We know that #sin60° = sqrt3/2#

So, A = 60°

Now we have to find cosA and tanA.

#cosA = cos60° = 1/2#

#tanA = tan60° = sqrt3#

Jim G.
Feb 3, 2018

#cosA=1/2" and "tanA=sqrt3#

Explanation:

#"using the "color(blue)"trigonometric identity"#

#•color(white)(x)sin^2A+cos^2A=1#

#rArrcosA=+-sqrt(1-sin^2A)#

#2sinA=sqrt3rArrsinA=sqrt3/2larr"acute angle"#

#rArrcosA=sqrt(1-(sqrt3/2)^2)#

#color(white)(rArrcosA)=sqrt(1-3/4)=sqrt(1/4)=1/2#

#rArrtanA=sinA/cosA=(sqrt3/2)/(1/2)=sqrt3#

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