Question #e6469
1 Answer
Feb 3, 2018
Explanation:
#"using the formula related to "color(blue)"arithmetic sequences"#
#•color(white)(x)a_n=a+(n-1)dlarrcolor(blue)"nth term"#
#•color(white)(x)S_n=n/2[2a+(n-1)d]larrcolor(blue)"sum to n terms"#
#"before we can calculate the sum of 10 terms we require"#
#"the values of a and d"#
#S_3=a+a+d+a+2d=18#
#rArr3a+3d=18to(1)#
#"in the same way the sum of terms 8, 9 and 10 is"#
#a+7d+a+8d+a+9d=81#
#rArr3a+24d=81to(2)#
#(2)-(1)" term by term eliminates a"#
#rArr21d=63rArrd=3#
#"substitute "d=3" in equation "(1)#
#3a+9=18#
#rArr3a=9rArra=3#
#rArrS_(10)=10/2[(2xx3)+(9xx3)]#
#color(white)(rArrS_(10))=5xx33=165#