Question #2e72e

1 Answer
Feb 5, 2018

#x=15625/12#

Explanation:

#"assuming you mean "1/3log_5(12x)=2#

#"using the "color(blue)"law of logarithms"#

#•color(white)(x)log_bx=nhArrx=b^n#

#"divide both sides by "1/3#

#rArrlog_5(12x)=2/(1/3)=6#

#rArr12x=5^6=15625#

#rArrx=15625/12#