Question #2e72e
1 Answer
Feb 5, 2018
Explanation:
#"assuming you mean "1/3log_5(12x)=2#
#"using the "color(blue)"law of logarithms"#
#•color(white)(x)log_bx=nhArrx=b^n#
#"divide both sides by "1/3#
#rArrlog_5(12x)=2/(1/3)=6#
#rArr12x=5^6=15625#
#rArrx=15625/12#