Question #15365

1 Answer
Feb 6, 2018

#LHS=(1+cos theta +sin theta)/(1+ cos theta-sin theta)#

#=(costheta(1+cos theta +sin theta))/(costheta(1+ cos theta-sin theta))#

#=(costheta(1+ sintheta)+cos^2 theta )/(costheta(1+ cos theta-sin theta))#

#=(costheta(1+ sintheta)+(1-sin^2 theta ))/(costheta(1+ cos theta-sin theta))#

#=((1+ sintheta)(costheta+1-sintheta ))/(costheta(1+ cos theta-sin theta))#

#=((1+ sintheta)cancel((1+costheta-sintheta )))/(costhetacancel((1+ cos theta-sin theta)))#

#=(1+sintheta)/costheta=RHS#