Question #db211

1 Answer
Feb 7, 2018

Please refer to the Explanation.

Explanation:

Prerequisite : #lim_(h to 0) (a^h-1)/h=lna, a >0#.

Now, in The Reqd. Lim. # L=lim_(y to 1)(x^(1-y)-1)/(1-y)#, let us

subst. #1-y=h," so that, as "y to 1; h to 0#.

#:. L=lim_(h to 0)(x^h-1)/h#,

#rArr L=lnx#.