# What is the general solution of the differential equation? : # dy/dx = 1/x^2 #

##### 1 Answer

Feb 7, 2018

# y =-1/x + C #

#### Explanation:

We have:

# dy/dx = 1/x^2 #

This is a First Order Separable Ordinary Differential Equation. We can *"separate the variables"* to get:

# int \ dy = int \ 1/x^2 \ dx #

Both integrals are standard calculus results , so integrating we get:

# y = x^(-1)/(-1) + C #

# \ \ = -1/x + C #

Which is the General Solution