Question

A gas enclosed in a piston at `100*mL` volume at `560*kPa` pressure, is expanded to `1000*mL` volume. What is the new pressure at constant temperature?

Answer 1

Well, given constant temperature....`P_1V_1=P_2V_2`

Explanation:

And so if volume is INCREASED tenfold from `100*mL` to `1000*mL`...PRESSURE will REDUCE by an equivalent factor, i.e. from `560*kPa` to `56*kPa`....