What is #sin(120^circ)#?

1 Answer
Feb 11, 2018

#sin(120^circ)=sqrt(3)/2#

Explanation:

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From the diagram above, we see that #120^circ# is equivalent to a reference angle of #60^circ# in Quadrant II.

Using standard triangles (as in the image) we see that the ratio of the height (derived using the Pythagorean Theorem) to the hypotenuse is #sqrt(3)/2#.
This ratio is (by definition) the value of #sin#

It should be acknowledged that if you want this value in a non-radical (approximation) form, then you will need to use a calculator to find #sqrt(3)#, in which case you might as well use the calculator to look up #sin(120^circ)# directly.