Question

Question #38190

Answer 1

The answer is `tanx+xsec^2x`

Explanation:

Using the product rule for differentiation ,
`dy/dx=xtanx`
Let x=u and v=tanx

By product rule ,
`dy/dx= v.du/dx + u.dv/dx` ------(i)

Now , `du/dx=1` and `dv/dx=sec^2x`

Substituting these into (i) you get ,
`dy/dx=tanx+xsec^2x`

`:.` The answer is `tanx + xsec^2x`