Question #a21ee

1 Answer
Feb 13, 2018

I=2tan(x/2)+C

Explanation:

We want to integrate

I=intsec^2(x/2)dx

Make a substitution u=x/2=>(du)/dx=1/2
(Hence the 2 in front of tan)

I=intsec^2(u)1/(1/2)du

=2intsec^2(u)du

=2tan(u)+C

Substitute u=x/2

=2tan(x/2)+C