# Question #5e2ed

Feb 14, 2018

0.399M

#### Explanation:

Molar mass of glucose: 180.156g/mol

Molarity of the solution is another way of asking for the concentration of the solution which can be represented in units of moles/liter.

First we look at our water content -

250.0g can be translated to 250.0mL assuming the density of water is 1.00g/mL, as demonstrated by:

$\frac{250 g}{1.00 \frac{g}{m L}}$ = 250.0mL

$250.0 m L \cdot \frac{1 L}{1000 m L}$ = 0.250L

Second, we need to calculate the number of moles of glucose we have:

$\frac{18.0 g}{180.156 \frac{g}{m o l}}$ = 0.0999moles

Lastly;

We have moles and L therefore,

0.0999Moles of glucose for every 0.250L, which continues to be:

0.0999Moles / 0.250 L = 0.399M (Mol/L)