# Question 281de

Feb 16, 2018

Alkenyl radicals with formula C4H7 are seven

#### Explanation:

Consider first the alkenes with formula C4H8:
They are
1) H2C=CH-CH2-CH3
2) H3C-CH=CH-CH3
3) H2C=C(CH3)2

From 1 there are three radicals possibles:

1a) H2C=CH-CH2-CH2
1b) H2C=CH-CH
-CH3
1c) H2C=C*-CH2-CH3

From 2 the possibilities are:

2a) H3C-CH=CH-CH2
2b) H3C-CH=C
-CH3

From 3:

3a) ${\text{H"_3"C-C=CH}}_{2}$
"color(white)(mmmmll)|
$\textcolor{w h i t e}{m m m m l} \text{CH"_2"*}$

3b) $\text{H"_3"C-C=CH*}$
$\textcolor{w h i t e}{m m m m l l} |$
$\textcolor{w h i t e}{m m m m l} {\text{CH}}_{3}$

Feb 16, 2018

I count ten alkenyl radicals with the formula ${\text{C"_4"H}}_{7}$.

#### Explanation:

From but-1-ene

1. ${\text{H"stackrelcolor(blue)(bb·)("C")"=CHCH"_2"CH}}_{3}$

2. ${\text{H"_2"C="stackrelcolor(blue)(bb·)("C")"CH"_2"CH}}_{3}$

3. ${\text{H"_2"C=CH"stackrelcolor(blue)(bb·)("C")"HCH}}_{3}$

4. ${\text{H"_2"C=CHCH"_2stackrelcolor(blue)(bb·)("C")"H}}_{2}$

From but-2-ene

5. and 6. stackrelcolor(blue)(bb·)("C")"H"_2"CH=CHCH"_3 ($E \text{-}$ and $Z \text{-}$isomers)

7. and 8. ${\text{CH"_3stackrelcolor(blue)(bb·)("C")"=CHCH}}_{3}$ ($E \text{-}$ and $Z \text{-}$isomers)

From 2-methylpropene

9. stackrelcolor(blue)(bb·)("C")"H"_2"C"("CH"_3)"=CH"_2

10. ("CH"_3)_2"C="stackrelcolor(blue)(bb·)("C")"H"#