Question

Question #5f024

Answer 1

The conversion is now
`1-i=sqrt2(cos315^@+isin315^@)`

Explanation:

`z=1-i`
`Re(z)=1`
`Im(z)=-1`
There by the complex number is situated in 4th quadrant
The amplitude being given by
`sqrt(Re(z)^2+Im(z)^2)=sqrt(1^2+(-1)^2`
Thus,
`|z|=sqrt2`
And
Argument being given byi
`tan^-1((Im(z))/(Re(z)))=tan^-1((-1)/1)`
`=-45^@`
Subtracting from `360^@`
Argument is `360-45=315`
Thus,
`theta=315`
The conversion is now
`1-i=sqrt2(cos315^@+isin315^@)`