# Question #19e41

Feb 25, 2018

$6 {x}^{2} - x - 1$

#### Explanation:

So you are given the 3 axis: $x , y$ and $z .$
$x = 3 x + 1$
$y = 2 x - 1$
$z = x + 1$

But you just need the area , so you will not use $z$
Therefore:
Area $= x \cdot y = \left(3 x + 1\right) \cdot \left(2 x - 1\right) = 6 {x}^{2} + 2 x - 3 x - 1 = 6 {x}^{2} - x - 1$