Question #35205

1 Answer
Mar 5, 2018

See details below

Explanation:

If we have a conductor vector #vecv(a,b,c)# let see how it will varies in relation to his components...

The easiest is the case #a=b=c=0#. In this case #vecv=vec0#

In case #a=0#, thus #vecv# belongs to the plane determined by axis #OY# and #OZ#. In this case we can express #vecv# as a linear combination in the canonic base of that plane. It's say:

#vecv=(0,b,c)=b(0,1,0)+c(0,0,1)#

In the other two cases (#b=0# or #c=0#) the reasoning is quite similar

#vecv=(a,0,c)=a(1,0,0)+c(0,0,1)#
#vecv=(a,b,0)=a(1,0,0)+b(0,1,0)#

And so on...