8.40g of NH4Cl is added to 10.6g of water. Calculate the molarity of the solution?

1 Answer
Jan 18, 2018

#"Concentration"-="Moles of solute"/"Volume of solution.."#

Explanation:

Now we have a #10.6*g# mass of water....and we ASSUME that after dissolution the solution has a volume of #10.6*mL-=10.6xx10^-3*L# (this may be right or wrong but no other data were supplied).

And so we take the quotient...#((8.40*g)/(53.49*g*mol^-1))/(10.6xx10^-3*L)=14.8*mol*L^-1#