# A 0.016 kg silver bracelet has a volume of 9.27 cm^3. What is its density?

Feb 11, 2017

$\rho \cong 1.7 \cdot g \cdot c {m}^{-} 3$

#### Explanation:

$\text{Density}$ $=$ $\text{Mass"/"Volume}$ $=$ $\frac{0.016 \cdot k g \times {10}^{3} \cdot g \cdot k {g}^{-} 1}{9.27 \cdot c {m}^{3}}$

$= 1.73 \cdot g \cdot c {m}^{-} 3$

Now chemists would usually use density values of $g \cdot m {L}^{-} 1$ or $g \cdot c {m}^{-} 3$. These can be converted into $k g \cdot {m}^{-} 3$, but these large values are inutile.

Note that I just looked over this question, and the calculated density is ABSURDLY low. So I would review your source. A typical value for silver metal would be $\rho = 10.5 \cdot g \cdot c {m}^{-} 3$.