A -0.06 C charge that is pointing downward is placed in a uniform electric field with a strength of 200 N/C. What is the magnitude and direction of the force on the charge?

1 Answer
Junaid Mirza
Apr 20, 2018

#12\ "N"# in the direction opposite to electric field.

Explanation:

Force on a charged particle #"q"# due to electric field #"E"# is given by

#vec"F" = "q"vec"E"#

#|"F"| = -0.06 cancel"C" xx 200\ "N"/cancel"C" = -"12 N"#

Here negative indicates that force is in the direction opposite to electric field.

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